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13043011343 is a prime number
BaseRepresentation
bin11000010010110110…
…01000111100001111
31020122222201121221012
430021123020330033
5203203002330333
65554124555435
7641134524065
oct141133107417
936588647835
1013043011343
11559349251a
1226400b2b7b
1312cb2810bb
148ba364035
155150eae48
hex3096c8f0f

13043011343 has 2 divisors, whose sum is σ = 13043011344. Its totient is φ = 13043011342.

The previous prime is 13043011297. The next prime is 13043011349. The reversal of 13043011343 is 34311034031.

13043011343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (34311034031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13043011343 - 26 = 13043011279 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13043011349) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6521505671 + 6521505672.

It is an arithmetic number, because the mean of its divisors is an integer number (6521505672).

Almost surely, 213043011343 is an apocalyptic number.

13043011343 is a deficient number, since it is larger than the sum of its proper divisors (1).

13043011343 is an equidigital number, since it uses as much as digits as its factorization.

13043011343 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 13043011343 its reverse (34311034031), we get a palindrome (47354045374).

The spelling of 13043011343 in words is "thirteen billion, forty-three million, eleven thousand, three hundred forty-three".