13043155535 has 4 divisors (see below), whose sum is σ = 15651786648. Its totient is φ = 10434524424.

The previous prime is 13043155459. The next prime is 13043155597. The reversal of 13043155535 is 53555134031.

13043155535 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13043155535 - 2¹² = 13043151439 is a prime.

It is a super-2 number, since 2×13043155535² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13043155495 and 13043155504.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1304315549 + ... + 1304315558.

It is an arithmetic number, because the mean of its divisors is an integer number (3912946662).

Almost surely, 2^13043155535 is an apocalyptic number.

13043155535 is a deficient number, since it is larger than the sum of its proper divisors (2608631113).

13043155535 is an equidigital number, since it uses as much as digits as its factorization.

13043155535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2608631112.

The product of its (nonzero) digits is 67500, while the sum is 35.

Adding to 13043155535 its reverse (53555134031), we get a palindrome (66598289566).

The spelling of 13043155535 in words is "thirteen billion, forty-three million, one hundred fifty-five thousand, five hundred thirty-five".