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130433115 = 3523735179
BaseRepresentation
bin1111100011001…
…00000001011011
3100002102200121010
413301210001123
5231342324430
620535345003
73142443321
oct761440133
9302380533
10130433115
116769836a
1237822163
132103a977
1413473d11
15b6b6cb0
hex7c6405b

130433115 has 32 divisors (see below), whose sum is σ = 220792320. Its totient is φ = 65615616.

The previous prime is 130433077. The next prime is 130433143. The reversal of 130433115 is 511334031.

It is not a de Polignac number, because 130433115 - 28 = 130432859 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130433091 and 130433100.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 22596 + ... + 27774.

It is an arithmetic number, because the mean of its divisors is an integer number (6899760).

Almost surely, 2130433115 is an apocalyptic number.

130433115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

130433115 is a deficient number, since it is larger than the sum of its proper divisors (90359205).

130433115 is a wasteful number, since it uses less digits than its factorization.

130433115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5283.

The product of its (nonzero) digits is 540, while the sum is 21.

The square root of 130433115 is about 11420.7318066751. The cubic root of 130433115 is about 507.1416610244.

Adding to 130433115 its reverse (511334031), we get a palindrome (641767146).

The spelling of 130433115 in words is "one hundred thirty million, four hundred thirty-three thousand, one hundred fifteen".

Divisors: 1 3 5 15 23 69 73 115 219 345 365 1095 1679 5037 5179 8395 15537 25185 25895 77685 119117 357351 378067 595585 1134201 1786755 1890335 5671005 8695541 26086623 43477705 130433115