130440000310020 has 144 divisors (see below), whose sum is σ = 403347709438128. Its totient is φ = 34112245063680.

The previous prime is 130440000310007. The next prime is 130440000310027. The reversal of 130440000310020 is 20013000044031.

It can be written as a sum of positive squares in 8 ways, for example, as 7601082084036 + 122838918225984 = 2757006^2 + 11083272^2 .

It is a super-2 number, since 2×130440000310020² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 130440000309975 and 130440000310002.

It is not an unprimeable number, because it can be changed into a prime (130440000310027) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 13925529 + ... + 21326048.

It is an arithmetic number, because the mean of its divisors is an integer number (2801025759987).

Almost surely, 2^{130440000310020} is an apocalyptic number.

130440000310020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

130440000310020 is an abundant number, since it is smaller than the sum of its proper divisors (272907709128108).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130440000310020 is a wasteful number, since it uses less digits than its factorization.

130440000310020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35251990 (or 35251985 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 18.

Adding to 130440000310020 its reverse (20013000044031), we get a palindrome (150453000354051).

The spelling of 130440000310020 in words is "one hundred thirty trillion, four hundred forty billion, three hundred ten thousand, twenty".