13044000041 has 8 divisors (see below), whose sum is σ = 13216596960. Its totient is φ = 12871770912.

The previous prime is 13044000037. The next prime is 13044000127. The reversal of 13044000041 is 14000044031.

13044000041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13044000041 - 2² = 13044000037 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13043999983 and 13044000019.

It is not an unprimeable number, because it can be changed into a prime (13044000001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20180 + ... + 162773.

It is an arithmetic number, because the mean of its divisors is an integer number (1652074620).

Almost surely, 2^13044000041 is an apocalyptic number.

It is an amenable number.

13044000041 is a deficient number, since it is larger than the sum of its proper divisors (172596919).

13044000041 is an equidigital number, since it uses as much as digits as its factorization.

13044000041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 183895.

The product of its (nonzero) digits is 192, while the sum is 17.

Adding to 13044000041 its reverse (14000044031), we get a palindrome (27044044072).

The spelling of 13044000041 in words is "thirteen billion, forty-four million, forty-one", and thus it is an aban number.