13044000042 has 24 divisors (see below), whose sum is σ = 29749474560. Its totient is φ = 4119157800.

The previous prime is 13044000037. The next prime is 13044000127. The reversal of 13044000042 is 24000044031.

13044000042 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 13043999979 and 13044000024.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 19069834 + ... + 19070517.

It is an arithmetic number, because the mean of its divisors is an integer number (1239561440).

Almost surely, 2^13044000042 is an apocalyptic number.

13044000042 is an abundant number, since it is smaller than the sum of its proper divisors (16705474518).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13044000042 is a wasteful number, since it uses less digits than its factorization.

13044000042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38140378 (or 38140375 counting only the distinct ones).

The product of its (nonzero) digits is 384, while the sum is 18.

Adding to 13044000042 its reverse (24000044031), we get a palindrome (37044044073).

The spelling of 13044000042 in words is "thirteen billion, forty-four million, forty-two", and thus it is an aban number.