Base | Representation |
---|---|
bin | 11101101010001001101110… |
… | …100101001100001001000111 |
3 | 122002211221110201020222211002 |
4 | 131222021232211030021013 |
5 | 114044112121034203333 |
6 | 1141231151514403515 |
7 | 36321660045165032 |
oct | 3552115645141107 |
9 | 562757421228732 |
10 | 130440012022343 |
11 | 3862033124a191 |
12 | 1276819413059b |
13 | 57a25955c4c9a |
14 | 242d48a37c019 |
15 | 101309da510e8 |
hex | 76a26e94c247 |
130440012022343 has 2 divisors, whose sum is σ = 130440012022344. Its totient is φ = 130440012022342.
The previous prime is 130440012022289. The next prime is 130440012022387. The reversal of 130440012022343 is 343220210044031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130440012022343 - 28 = 130440012022087 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130440012022043) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220006011171 + 65220006011172.
It is an arithmetic number, because the mean of its divisors is an integer number (65220006011172).
Almost surely, 2130440012022343 is an apocalyptic number.
130440012022343 is a deficient number, since it is larger than the sum of its proper divisors (1).
130440012022343 is an equidigital number, since it uses as much as digits as its factorization.
130440012022343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 130440012022343 its reverse (343220210044031), we get a palindrome (473660222066374).
The spelling of 130440012022343 in words is "one hundred thirty trillion, four hundred forty billion, twelve million, twenty-two thousand, three hundred forty-three".
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