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130440012022343 is a prime number
BaseRepresentation
bin11101101010001001101110…
…100101001100001001000111
3122002211221110201020222211002
4131222021232211030021013
5114044112121034203333
61141231151514403515
736321660045165032
oct3552115645141107
9562757421228732
10130440012022343
113862033124a191
121276819413059b
1357a25955c4c9a
14242d48a37c019
15101309da510e8
hex76a26e94c247

130440012022343 has 2 divisors, whose sum is σ = 130440012022344. Its totient is φ = 130440012022342.

The previous prime is 130440012022289. The next prime is 130440012022387. The reversal of 130440012022343 is 343220210044031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130440012022343 - 28 = 130440012022087 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130440012022043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220006011171 + 65220006011172.

It is an arithmetic number, because the mean of its divisors is an integer number (65220006011172).

Almost surely, 2130440012022343 is an apocalyptic number.

130440012022343 is a deficient number, since it is larger than the sum of its proper divisors (1).

130440012022343 is an equidigital number, since it uses as much as digits as its factorization.

130440012022343 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 130440012022343 its reverse (343220210044031), we get a palindrome (473660222066374).

The spelling of 130440012022343 in words is "one hundred thirty trillion, four hundred forty billion, twelve million, twenty-two thousand, three hundred forty-three".