13044014121167 has 2 divisors, whose sum is σ = 13044014121168. Its totient is φ = 13044014121166.

The previous prime is 13044014121041. The next prime is 13044014121169. The reversal of 13044014121167 is 76112141044031.

13044014121167 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13044014121167 - 2¹⁰ = 13044014120143 is a prime.

Together with 13044014121169, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13044014121169) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522007060583 + 6522007060584.

It is an arithmetic number, because the mean of its divisors is an integer number (6522007060584).

Almost surely, 2^{13044014121167} is an apocalyptic number.

13044014121167 is a deficient number, since it is larger than the sum of its proper divisors (1).

13044014121167 is an equidigital number, since it uses as much as digits as its factorization.

13044014121167 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16128, while the sum is 35.

Adding to 13044014121167 its reverse (76112141044031), we get a palindrome (89156155165198).

The spelling of 13044014121167 in words is "thirteen trillion, forty-four billion, fourteen million, one hundred twenty-one thousand, one hundred sixty-seven".