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13044044013000 = 23353711134343671
BaseRepresentation
bin1011110111010000110110…
…0111000001110111001000
31201011222221212002012201020
42331310031213001313020
53202203200231404000
643424203500352440
72514254366466510
oct275641547016710
951158855065636
1013044044013000
114179a47873640
121568033b45720
137380817cc680
14331499722840
1517948b1d9ba0
hexbdd0d9c1dc8

13044044013000 has 512 divisors, whose sum is σ = 54642698772480. Its totient is φ = 2501953920000.

The previous prime is 13044044012971. The next prime is 13044044013017. The reversal of 13044044013000 is 31044044031.

It is a super-2 number, since 2×130440440130002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 831165 + ... + 5174835.

It is an arithmetic number, because the mean of its divisors is an integer number (106724021040).

Almost surely, 213044044013000 is an apocalyptic number.

13044044013000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13044044013000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (27321349386240).

13044044013000 is an abundant number, since it is smaller than the sum of its proper divisors (41598654759480).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13044044013000 is a wasteful number, since it uses less digits than its factorization.

13044044013000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4343726 (or 4343712 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 24.

Adding to 13044044013000 its reverse (31044044031), we get a palindrome (13075088057031).

The spelling of 13044044013000 in words is "thirteen trillion, forty-four billion, forty-four million, thirteen thousand".