13044103122433 has 4 divisors (see below), whose sum is σ = 13067027733060. Its totient is φ = 13021178511808.

The previous prime is 13044103122403. The next prime is 13044103122443. The reversal of 13044103122433 is 33422130144031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6982742830144 + 6061360292289 = 2642488^2 + 2461983^2 .

It is a cyclic number.

It is not a de Polignac number, because 13044103122433 - 2³³ = 13035513187841 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13044103122395 and 13044103122404.

It is not an unprimeable number, because it can be changed into a prime (13044103122403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11462304460 + ... + 11462305597.

It is an arithmetic number, because the mean of its divisors is an integer number (3266756933265).

Almost surely, 2^{13044103122433} is an apocalyptic number.

It is an amenable number.

13044103122433 is a deficient number, since it is larger than the sum of its proper divisors (22924610627).

13044103122433 is an equidigital number, since it uses as much as digits as its factorization.

13044103122433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22924610626.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 13044103122433 its reverse (33422130144031), we get a palindrome (46466233266464).

The spelling of 13044103122433 in words is "thirteen trillion, forty-four billion, one hundred three million, one hundred twenty-two thousand, four hundred thirty-three".