130441031241440 has 48 divisors (see below), whose sum is σ = 324386248752720. Its totient is φ = 49430285521920.

The previous prime is 130441031241439. The next prime is 130441031241473. The reversal of 130441031241440 is 44142130144031.

It is a super-3 number, since 3×130441031241440³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (32).

It is a junction number, because it is equal to n+sod(n) for n = 130441031241397 and 130441031241406.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21454113941 + ... + 21454120020.

It is an arithmetic number, because the mean of its divisors is an integer number (6758046849015).

Almost surely, 2^{130441031241440} is an apocalyptic number.

130441031241440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

130441031241440 is an abundant number, since it is smaller than the sum of its proper divisors (193945217511280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130441031241440 is a wasteful number, since it uses less digits than its factorization.

130441031241440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 42908233995 (or 42908233987 counting only the distinct ones).

The product of its (nonzero) digits is 18432, while the sum is 32.

Adding to 130441031241440 its reverse (44142130144031), we get a palindrome (174583161385471).

The spelling of 130441031241440 in words is "one hundred thirty trillion, four hundred forty-one billion, thirty-one million, two hundred forty-one thousand, four hundred forty".