13044133 has 4 divisors (see below), whose sum is σ = 13265280. Its totient is φ = 12822988.

The previous prime is 13044131. The next prime is 13044137. The reversal of 13044133 is 33144031.

13044133 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33144031 = 41 ⋅808391.

It is a cyclic number.

It is not a de Polignac number, because 13044133 - 2¹ = 13044131 is a prime.

It is a Duffinian number.

It is a plaindrome in base 15.

It is a self number, because there is not a number n which added to its sum of digits gives 13044133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13044131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 110485 + ... + 110602.

It is an arithmetic number, because the mean of its divisors is an integer number (3316320).

Almost surely, 2^13044133 is an apocalyptic number.

It is an amenable number.

13044133 is a deficient number, since it is larger than the sum of its proper divisors (221147).

13044133 is an equidigital number, since it uses as much as digits as its factorization.

13044133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 221146.

The product of its (nonzero) digits is 432, while the sum is 19.

The square root of 13044133 is about 3611.6662359637. Note that the first 3 decimals coincide. The cubic root of 13044133 is about 235.3992488884.

Adding to 13044133 its reverse (33144031), we get a palindrome (46188164).

The spelling of 13044133 in words is "thirteen million, forty-four thousand, one hundred thirty-three".