Base | Representation |
---|---|
bin | 10010111110110110110… |
… | …001000011011011101111 |
3 | 11121200222202122002220222 |
4 | 102332312301003123233 |
5 | 132332443444344434 |
6 | 2435130242201555 |
7 | 163146162660461 |
oct | 22766661033357 |
9 | 4550882562828 |
10 | 1304441403119 |
11 | 463235190088 |
12 | 1909869532bb |
13 | 960152c581a |
14 | 471c73a0131 |
15 | 23de8cdb72e |
hex | 12fb6c436ef |
1304441403119 has 2 divisors, whose sum is σ = 1304441403120. Its totient is φ = 1304441403118.
The previous prime is 1304441403113. The next prime is 1304441403121. The reversal of 1304441403119 is 9113041444031.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1304441403119 - 216 = 1304441337583 is a prime.
It is a super-2 number, since 2×13044414031192 (a number of 25 digits) contains 22 as substring.
Together with 1304441403121, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1304441403113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652220701559 + 652220701560.
It is an arithmetic number, because the mean of its divisors is an integer number (652220701560).
Almost surely, 21304441403119 is an apocalyptic number.
1304441403119 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304441403119 is an equidigital number, since it uses as much as digits as its factorization.
1304441403119 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20736, while the sum is 35.
The spelling of 1304441403119 in words is "one trillion, three hundred four billion, four hundred forty-one million, four hundred three thousand, one hundred nineteen".
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