Base | Representation |
---|---|
bin | 1011110111010010010101… |
… | …0001110111110101110000 |
3 | 1201012000222112022100021001 |
4 | 2331310211101313311300 |
5 | 3202210003411320422 |
6 | 43424311124011344 |
7 | 2514300261032263 |
oct | 275644521676560 |
9 | 51160875270231 |
10 | 13044441120112 |
11 | 417a130a43036 |
12 | 1568124b30b54 |
13 | 738115b6a2ac |
14 | 3314d6372cda |
15 | 1794b0ecb227 |
hex | bdd25477d70 |
13044441120112 has 10 divisors (see below), whose sum is σ = 25273604670248. Its totient is φ = 6522220560048.
The previous prime is 13044441120107. The next prime is 13044441120121. The reversal of 13044441120112 is 21102114444031.
It is a happy number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 407638784988 + ... + 407638785019.
Almost surely, 213044441120112 is an apocalyptic number.
It is an amenable number.
13044441120112 is a deficient number, since it is larger than the sum of its proper divisors (12229163550136).
13044441120112 is an equidigital number, since it uses as much as digits as its factorization.
13044441120112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 815277570015 (or 815277570009 counting only the distinct ones).
The product of its (nonzero) digits is 3072, while the sum is 28.
Adding to 13044441120112 its reverse (21102114444031), we get a palindrome (34146555564143).
The spelling of 13044441120112 in words is "thirteen trillion, forty-four billion, four hundred forty-one million, one hundred twenty thousand, one hundred twelve".
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