Base | Representation |
---|---|
bin | 1011110111100001110011… |
… | …0010001001101110000001 |
3 | 1201012102200220211212010001 |
4 | 2331320130302021232001 |
5 | 3202242004422214210 |
6 | 43430235141040001 |
7 | 2514505212114361 |
oct | 275703462115601 |
9 | 51172626755101 |
10 | 13048593554305 |
11 | 4180971981331 |
12 | 1568aa36b6001 |
13 | 73862823084a |
14 | 3317aba469a1 |
15 | 17965581203a |
hex | bde1cc89b81 |
13048593554305 has 16 divisors (see below), whose sum is σ = 16340710068864. Its totient is φ = 9984031953280.
The previous prime is 13048593554281. The next prime is 13048593554327. The reversal of 13048593554305 is 50345539584031.
13048593554305 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13048593554305 - 25 = 13048593554273 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4381804 + ... + 6730333.
It is an arithmetic number, because the mean of its divisors is an integer number (1021294379304).
Almost surely, 213048593554305 is an apocalyptic number.
It is an amenable number.
13048593554305 is a deficient number, since it is larger than the sum of its proper divisors (3292116514559).
13048593554305 is a wasteful number, since it uses less digits than its factorization.
13048593554305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11122376.
The product of its (nonzero) digits is 19440000, while the sum is 55.
The spelling of 13048593554305 in words is "thirteen trillion, forty-eight billion, five hundred ninety-three million, five hundred fifty-four thousand, three hundred five".
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