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13050175693 is a prime number
BaseRepresentation
bin11000010011101100…
…11110000011001101
31020200111012121120111
430021312132003031
5203211321110233
65554542320021
7641252443312
oct141166360315
936614177514
1013050175693
115597536175
122642589011
1312cc8bc069
148bb2aad09
15515a63acd
hex309d9e0cd

13050175693 has 2 divisors, whose sum is σ = 13050175694. Its totient is φ = 13050175692.

The previous prime is 13050175667. The next prime is 13050175807. The reversal of 13050175693 is 39657105031.

It is a happy number.

13050175693 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12937242564 + 112933129 = 113742^2 + 10627^2 .

It is a cyclic number.

It is not a de Polignac number, because 13050175693 - 233 = 4460241101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13050115693) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6525087846 + 6525087847.

It is an arithmetic number, because the mean of its divisors is an integer number (6525087847).

Almost surely, 213050175693 is an apocalyptic number.

It is an amenable number.

13050175693 is a deficient number, since it is larger than the sum of its proper divisors (1).

13050175693 is an equidigital number, since it uses as much as digits as its factorization.

13050175693 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 85050, while the sum is 40.

The spelling of 13050175693 in words is "thirteen billion, fifty million, one hundred seventy-five thousand, six hundred ninety-three".