13052112431 has 2 divisors, whose sum is σ = 13052112432. Its totient is φ = 13052112430.

The previous prime is 13052112343. The next prime is 13052112433. The reversal of 13052112431 is 13421125031.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13052112431 is a prime.

It is a super-2 number, since 2×13052112431² (a number of 21 digits) contains 22 as substring.

Together with 13052112433, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13052112397 and 13052112406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13052112433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6526056215 + 6526056216.

It is an arithmetic number, because the mean of its divisors is an integer number (6526056216).

Almost surely, 2^13052112431 is an apocalyptic number.

13052112431 is a deficient number, since it is larger than the sum of its proper divisors (1).

13052112431 is an equidigital number, since it uses as much as digits as its factorization.

13052112431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 13052112431 its reverse (13421125031), we get a palindrome (26473237462).

The spelling of 13052112431 in words is "thirteen billion, fifty-two million, one hundred twelve thousand, four hundred thirty-one".