Base | Representation |
---|---|
bin | 11000010011111011… |
… | …10110111000110101 |
3 | 1020200121212000021202 |
4 | 30021331312320311 |
5 | 203212320044222 |
6 | 5555052022245 |
7 | 641305060640 |
oct | 141175667065 |
9 | 36617760252 |
10 | 13052112437 |
11 | 5598639291 |
12 | 2643161985 |
13 | 1300119770 |
14 | 8bb652a57 |
15 | 515ce7892 |
hex | 309f76e35 |
13052112437 has 16 divisors (see below), whose sum is σ = 16082935680. Its totient is φ = 10314862272.
The previous prime is 13052112433. The next prime is 13052112439. The reversal of 13052112437 is 73421125031.
It is not a de Polignac number, because 13052112437 - 22 = 13052112433 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13052112431) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5318 + ... + 161655.
It is an arithmetic number, because the mean of its divisors is an integer number (1005183480).
Almost surely, 213052112437 is an apocalyptic number.
It is an amenable number.
13052112437 is a deficient number, since it is larger than the sum of its proper divisors (3030823243).
13052112437 is a wasteful number, since it uses less digits than its factorization.
13052112437 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 167852.
The product of its (nonzero) digits is 5040, while the sum is 29.
Adding to 13052112437 its reverse (73421125031), we get a palindrome (86473237468).
The spelling of 13052112437 in words is "thirteen billion, fifty-two million, one hundred twelve thousand, four hundred thirty-seven".
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