Base | Representation |
---|---|
bin | 1011110111111001110111… |
… | …0010000011000011100111 |
3 | 1201020001101001222020221220 |
4 | 2331332131302003003213 |
5 | 3202343222001131200 |
6 | 43433224120111423 |
7 | 2515124243322654 |
oct | 275763562030347 |
9 | 51201331866856 |
10 | 13055052755175 |
11 | 4183686a32572 |
12 | 156a1a6905573 |
13 | 7391174981b2 |
14 | 331c2182ac2b |
15 | 1798d29044a0 |
hex | bdf9dc830e7 |
13055052755175 has 12 divisors (see below), whose sum is σ = 21584353888680. Its totient is φ = 6962694802720.
The previous prime is 13055052755167. The next prime is 13055052755179. The reversal of 13055052755175 is 57155725055031.
It is a happy number.
It is not a de Polignac number, because 13055052755175 - 23 = 13055052755167 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13055052755179) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 87033684960 + ... + 87033685109.
It is an arithmetic number, because the mean of its divisors is an integer number (1798696157390).
Almost surely, 213055052755175 is an apocalyptic number.
13055052755175 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13055052755175 is a deficient number, since it is larger than the sum of its proper divisors (8529301133505).
13055052755175 is a wasteful number, since it uses less digits than its factorization.
13055052755175 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 174067370082 (or 174067370077 counting only the distinct ones).
The product of its (nonzero) digits is 4593750, while the sum is 51.
The spelling of 13055052755175 in words is "thirteen trillion, fifty-five billion, fifty-two million, seven hundred fifty-five thousand, one hundred seventy-five".
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