Base | Representation |
---|---|
bin | 1011110111111101100100… |
… | …1111100011110001011100 |
3 | 1201020010221121010011210222 |
4 | 2331333121033203301130 |
5 | 3202402242342101400 |
6 | 43433511114020512 |
7 | 2515161045604145 |
oct | 275773117436134 |
9 | 51203847104728 |
10 | 13056050347100 |
11 | 4184049061102 |
12 | 156a424a17738 |
13 | 739246071287 |
14 | 331cb810cacc |
15 | 1799402ac185 |
hex | bdfd93e3c5c |
13056050347100 has 36 divisors (see below), whose sum is σ = 28331818095504. Its totient is φ = 5222385329280.
The previous prime is 13056050347069. The next prime is 13056050347141. The reversal of 13056050347100 is 174305065031.
It is a super-3 number, since 3×130560503471003 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 18930929 + ... + 19608471.
Almost surely, 213056050347100 is an apocalyptic number.
13056050347100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13056050347100 is an abundant number, since it is smaller than the sum of its proper divisors (15275767748404).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13056050347100 is a wasteful number, since it uses less digits than its factorization.
13056050347100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 870254 (or 870247 counting only the distinct ones).
The product of its (nonzero) digits is 37800, while the sum is 35.
The spelling of 13056050347100 in words is "thirteen trillion, fifty-six billion, fifty million, three hundred forty-seven thousand, one hundred".
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