Base | Representation |
---|---|
bin | 10011000000011010111… |
… | …101101011011001001000 |
3 | 11121212022220210022221102 |
4 | 103000122331223121020 |
5 | 132344414320342440 |
6 | 2440005132400532 |
7 | 163235634336500 |
oct | 23003275533110 |
9 | 4555286708842 |
10 | 1306122434120 |
11 | 463a180775a9 |
12 | 191175916148 |
13 | 9622266001a |
14 | 47306748a00 |
15 | 23e96694b15 |
hex | 1301af6b648 |
1306122434120 has 48 divisors (see below), whose sum is σ = 3418575559740. Its totient is φ = 447813405312.
The previous prime is 1306122434119. The next prime is 1306122434143. The reversal of 1306122434120 is 214342216031.
It can be written as a sum of positive squares in 2 ways, for example, as 1279898518276 + 26223915844 = 1131326^2 + 161938^2 .
It is a super-3 number, since 3×13061224341203 (a number of 37 digits) contains 333 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 333192539 + ... + 333196458.
Almost surely, 21306122434120 is an apocalyptic number.
1306122434120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1306122434120 is an abundant number, since it is smaller than the sum of its proper divisors (2112453125620).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1306122434120 is a wasteful number, since it uses less digits than its factorization.
1306122434120 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 666389022 (or 666389011 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 29.
The spelling of 1306122434120 in words is "one trillion, three hundred six billion, one hundred twenty-two million, four hundred thirty-four thousand, one hundred twenty".
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