Base | Representation |
---|---|
bin | 11101101100101100001000… |
… | …111111010110011010000011 |
3 | 122010110121121012101022111212 |
4 | 131230230020333112122003 |
5 | 114104441243210410420 |
6 | 1141443232205200335 |
7 | 36340402424240621 |
oct | 3554541077263203 |
9 | 563417535338455 |
10 | 130614401263235 |
11 | 38688290447a6a |
12 | 12795b428600ab |
13 | 57b5b679b5b16 |
14 | 2437ab0d2c511 |
15 | 10178a88ac3c5 |
hex | 76cb08fd6683 |
130614401263235 has 16 divisors (see below), whose sum is σ = 168827815157760. Its totient is φ = 96724269095520.
The previous prime is 130614401263037. The next prime is 130614401263243. The reversal of 130614401263235 is 532362104416031.
It is a happy number.
It is not a de Polignac number, because 130614401263235 - 226 = 130614334154371 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130614401263192 and 130614401263201.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 18318986795 + ... + 18318993924.
It is an arithmetic number, because the mean of its divisors is an integer number (10551738447360).
Almost surely, 2130614401263235 is an apocalyptic number.
130614401263235 is a deficient number, since it is larger than the sum of its proper divisors (38213413894525).
130614401263235 is a wasteful number, since it uses less digits than its factorization.
130614401263235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 36637980778.
The product of its (nonzero) digits is 311040, while the sum is 41.
Adding to 130614401263235 its reverse (532362104416031), we get a palindrome (662976505679266).
The spelling of 130614401263235 in words is "one hundred thirty trillion, six hundred fourteen billion, four hundred one million, two hundred sixty-three thousand, two hundred thirty-five".
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