13062603262439 has 2 divisors, whose sum is σ = 13062603262440. Its totient is φ = 13062603262438.

The previous prime is 13062603262433. The next prime is 13062603262441. The reversal of 13062603262439 is 93426230626031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13062603262439 - 2³² = 13058308295143 is a prime.

Together with 13062603262441, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13062603262393 and 13062603262402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13062603262433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6531301631219 + 6531301631220.

It is an arithmetic number, because the mean of its divisors is an integer number (6531301631220).

Almost surely, 2^{13062603262439} is an apocalyptic number.

13062603262439 is a deficient number, since it is larger than the sum of its proper divisors (1).

13062603262439 is an equidigital number, since it uses as much as digits as its factorization.

13062603262439 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1679616, while the sum is 47.

The spelling of 13062603262439 in words is "thirteen trillion, sixty-two billion, six hundred three million, two hundred sixty-two thousand, four hundred thirty-nine".