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13062603262441 is a prime number
BaseRepresentation
bin1011111000010101111111…
…0100111100100111101001
31201020202212021120202202011
42332011133310330213221
53203004202413344231
643440513241435521
72515512325505455
oct276053764744751
951222767522664
1013062603262441
114186901000417
12156b75349bba1
13739a4b85b485
1433233a529665
15179bc57119b1
hexbe15fd3c9e9

13062603262441 has 2 divisors, whose sum is σ = 13062603262442. Its totient is φ = 13062603262440.

The previous prime is 13062603262439. The next prime is 13062603262543. The reversal of 13062603262441 is 14426230626031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13018955696041 + 43647566400 = 3608179^2 + 208920^2 .

It is a cyclic number.

It is not a de Polignac number, because 13062603262441 - 21 = 13062603262439 is a prime.

Together with 13062603262439, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 13062603262394 and 13062603262403.

It is not a weakly prime, because it can be changed into another prime (13062603242441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6531301631220 + 6531301631221.

It is an arithmetic number, because the mean of its divisors is an integer number (6531301631221).

Almost surely, 213062603262441 is an apocalyptic number.

It is an amenable number.

13062603262441 is a deficient number, since it is larger than the sum of its proper divisors (1).

13062603262441 is an equidigital number, since it uses as much as digits as its factorization.

13062603262441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 248832, while the sum is 40.

Adding to 13062603262441 its reverse (14426230626031), we get a palindrome (27488833888472).

The spelling of 13062603262441 in words is "thirteen trillion, sixty-two billion, six hundred three million, two hundred sixty-two thousand, four hundred forty-one".