Base | Representation |
---|---|
bin | 1011111010100001010011… |
… | …0111010111100000000110 |
3 | 1201101100101112201200112220 |
4 | 2332220110313113200012 |
5 | 3204112300034430202 |
6 | 43510020154153210 |
7 | 2521305135254442 |
oct | 276502467274006 |
9 | 51340345650486 |
10 | 13100000311302 |
11 | 41a0751728773 |
12 | 1576a4b722806 |
13 | 74042b576758 |
14 | 334087127822 |
15 | 17ab63933abc |
hex | bea14dd7806 |
13100000311302 has 64 divisors (see below), whose sum is σ = 28246939902720. Its totient is φ = 4035275836416.
The previous prime is 13100000311301. The next prime is 13100000311309. The reversal of 13100000311302 is 20311300000131.
13100000311302 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×131000003113022 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13100000311301) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1023927 + ... + 5220002.
It is an arithmetic number, because the mean of its divisors is an integer number (441358435980).
Almost surely, 213100000311302 is an apocalyptic number.
13100000311302 is an abundant number, since it is smaller than the sum of its proper divisors (15146939591418).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13100000311302 is a wasteful number, since it uses less digits than its factorization.
13100000311302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6244325.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 13100000311302 its reverse (20311300000131), we get a palindrome (33411300311433).
The spelling of 13100000311302 in words is "thirteen trillion, one hundred billion, three hundred eleven thousand, three hundred two".
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