Base | Representation |
---|---|
bin | 11101110010010011010010… |
… | …010000010010011111011000 |
3 | 122011211110222022220112220021 |
4 | 131302103102100102133120 |
5 | 114132301030140412100 |
6 | 1142340325531440224 |
7 | 36410303602443232 |
oct | 3562232220223730 |
9 | 564743868815807 |
10 | 131000030013400 |
11 | 38816889862689 |
12 | 12838824bb6074 |
13 | 5813332b2bb22 |
14 | 244c6145b9252 |
15 | 102292878ca1a |
hex | 7724d24127d8 |
131000030013400 has 24 divisors (see below), whose sum is σ = 304575069781620. Its totient is φ = 52400012005280.
The previous prime is 131000030013367. The next prime is 131000030013403. The reversal of 131000030013400 is 4310030000131.
It is a super-2 number, since 2×1310000300134002 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131000030013403) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 327500074834 + ... + 327500075233.
Almost surely, 2131000030013400 is an apocalyptic number.
131000030013400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131000030013400 is an abundant number, since it is smaller than the sum of its proper divisors (173575039768220).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131000030013400 is a wasteful number, since it uses less digits than its factorization.
131000030013400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 655000150083 (or 655000150074 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 16.
Adding to 131000030013400 its reverse (4310030000131), we get a palindrome (135310060013531).
The spelling of 131000030013400 in words is "one hundred thirty-one trillion, thirty million, thirteen thousand, four hundred".
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