13100012311 has 2 divisors, whose sum is σ = 13100012312. Its totient is φ = 13100012310.

The previous prime is 13100012309. The next prime is 13100012323. The reversal of 13100012311 is 11321000131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13100012311 - 2¹ = 13100012309 is a prime.

It is a super-2 number, since 2×13100012311² (a number of 21 digits) contains 22 as substring.

Together with 13100012309, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 13100012291 and 13100012300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13100012111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550006155 + 6550006156.

It is an arithmetic number, because the mean of its divisors is an integer number (6550006156).

Almost surely, 2^13100012311 is an apocalyptic number.

13100012311 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100012311 is an equidigital number, since it uses as much as digits as its factorization.

13100012311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 13100012311 its reverse (11321000131), we get a palindrome (24421012442).

The spelling of 13100012311 in words is "thirteen billion, one hundred million, twelve thousand, three hundred eleven".