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131000200003200 = 273521110115837759
BaseRepresentation
bin11101110010010011011100…
…011000101111111010000000
3122011211111102011202221001210
4131302103130120233322000
5114132301402200100300
61142340354443130120
736410311035360303
oct3562233430577200
9564744364687053
10131000200003200
1138816966808520
1212838871b13940
13581335c1095c8
14244c62cdc8b3a
15102293866a050
hex7724dc62fe80

131000200003200 has 768 divisors, whose sum is σ = 475729608499200. Its totient is φ = 31419279360000.

The previous prime is 131000200003177. The next prime is 131000200003213. The reversal of 131000200003200 is 2300002000131.

It is a happy number.

It is a super-3 number, since 3×1310002000032003 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 16883640921 + ... + 16883648679.

It is an arithmetic number, because the mean of its divisors is an integer number (619439594400).

Almost surely, 2131000200003200 is an apocalyptic number.

131000200003200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131000200003200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (237864804249600).

131000200003200 is an abundant number, since it is smaller than the sum of its proper divisors (344729408496000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131000200003200 is a wasteful number, since it uses less digits than its factorization.

131000200003200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9481 (or 9464 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 12.

Adding to 131000200003200 its reverse (2300002000131), we get a palindrome (133300202003331).

The spelling of 131000200003200 in words is "one hundred thirty-one trillion, two hundred million, three thousand, two hundred".