Base | Representation |
---|---|
bin | 11101110010010011011100… |
… | …100101010111101111111000 |
3 | 122011211111102102000001001101 |
4 | 131302103130211113233320 |
5 | 114132301404021441440 |
6 | 1142340355042101144 |
7 | 36410311105451302 |
oct | 3562233445275770 |
9 | 564744372001041 |
10 | 131000203312120 |
11 | 3881696866856a |
12 | 1283887304a7b4 |
13 | 581335c9c774c |
14 | 244c62d60a972 |
15 | 1022938ac069a |
hex | 7724dc957bf8 |
131000203312120 has 16 divisors (see below), whose sum is σ = 294750457452360. Its totient is φ = 52400081324832.
The previous prime is 131000203312103. The next prime is 131000203312123. The reversal of 131000203312120 is 21213302000131.
It is a super-2 number, since 2×1310002033121202 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131000203312123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1637502541362 + ... + 1637502541441.
Almost surely, 2131000203312120 is an apocalyptic number.
131000203312120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131000203312120 is an abundant number, since it is smaller than the sum of its proper divisors (163750254140240).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131000203312120 is a wasteful number, since it uses less digits than its factorization.
131000203312120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3275005082814 (or 3275005082810 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 131000203312120 its reverse (21213302000131), we get a palindrome (152213505312251).
The spelling of 131000203312120 in words is "one hundred thirty-one trillion, two hundred three million, three hundred twelve thousand, one hundred twenty".
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