131000204020111 has 2 divisors, whose sum is σ = 131000204020112. Its totient is φ = 131000204020110.

The previous prime is 131000204020099. The next prime is 131000204020201. The reversal of 131000204020111 is 111020402000131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131000204020111 is a prime.

It is a super-2 number, since 2×131000204020111² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131000204023111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500102010055 + 65500102010056.

It is an arithmetic number, because the mean of its divisors is an integer number (65500102010056).

Almost surely, 2^{131000204020111} is an apocalyptic number.

131000204020111 is a deficient number, since it is larger than the sum of its proper divisors (1).

131000204020111 is an equidigital number, since it uses as much as digits as its factorization.

131000204020111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 131000204020111 its reverse (111020402000131), we get a palindrome (242020606020242).

The spelling of 131000204020111 in words is "one hundred thirty-one trillion, two hundred four million, twenty thousand, one hundred eleven".