131000204023111 has 2 divisors, whose sum is σ = 131000204023112. Its totient is φ = 131000204023110.

The previous prime is 131000204023037. The next prime is 131000204023177. The reversal of 131000204023111 is 111320402000131.

It is a strong prime.

It is an emirp because it is prime and its reverse (111320402000131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131000204023111 - 2²¹ = 131000201925959 is a prime.

It is a super-2 number, since 2×131000204023111² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131000204020111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500102011555 + 65500102011556.

It is an arithmetic number, because the mean of its divisors is an integer number (65500102011556).

Almost surely, 2^{131000204023111} is an apocalyptic number.

131000204023111 is a deficient number, since it is larger than the sum of its proper divisors (1).

131000204023111 is an equidigital number, since it uses as much as digits as its factorization.

131000204023111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 131000204023111 its reverse (111320402000131), we get a palindrome (242320606023242).

The spelling of 131000204023111 in words is "one hundred thirty-one trillion, two hundred four million, twenty-three thousand, one hundred eleven".