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13100030204003 is a prime number
BaseRepresentation
bin1011111010100001011010…
…1001011001100001100011
31201101100110121222101121222
42332220112221121201203
53204112330213012003
643510023143005255
72521305650325251
oct276502651314143
951340417871558
1013100030204003
1141a0767595586
121576a5973982b
13740434811942
1433408b0a95d1
1517ab6638ac38
hexbea16a59863

13100030204003 has 2 divisors, whose sum is σ = 13100030204004. Its totient is φ = 13100030204002.

The previous prime is 13100030203999. The next prime is 13100030204011. The reversal of 13100030204003 is 30040203000131.

It is a happy number.

13100030204003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (30040203000131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13100030204003 - 22 = 13100030203999 is a prime.

It is a super-2 number, since 2×131000302040032 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13100030204083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550015102001 + 6550015102002.

It is an arithmetic number, because the mean of its divisors is an integer number (6550015102002).

Almost surely, 213100030204003 is an apocalyptic number.

13100030204003 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100030204003 is an equidigital number, since it uses as much as digits as its factorization.

13100030204003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 17.

Adding to 13100030204003 its reverse (30040203000131), we get a palindrome (43140233204134).

The spelling of 13100030204003 in words is "thirteen trillion, one hundred billion, thirty million, two hundred four thousand, three".