Base | Representation |
---|---|
bin | 11101110010010011100010… |
… | …100110101100111011001100 |
3 | 122011211111200110001222201020 |
4 | 131302103202212230323030 |
5 | 114132302110401334200 |
6 | 1142340413051114140 |
7 | 36410313443160405 |
oct | 3562234246547314 |
9 | 564744613058636 |
10 | 131000304324300 |
11 | 38816a0a690504 |
12 | 128388a0a42950 |
13 | 5813377903b78 |
14 | 244c63cbc29ac |
15 | 10229428c4ea0 |
hex | 7724e29acecc |
131000304324300 has 36 divisors (see below), whose sum is σ = 379027547179176. Its totient is φ = 34933414486400.
The previous prime is 131000304324293. The next prime is 131000304324313. The reversal of 131000304324300 is 3423403000131.
It is a super-2 number, since 2×1310003043243002 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 218333840241 + ... + 218333840840.
Almost surely, 2131000304324300 is an apocalyptic number.
131000304324300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131000304324300 is an abundant number, since it is smaller than the sum of its proper divisors (248027242854876).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131000304324300 is a wasteful number, since it uses less digits than its factorization.
131000304324300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 436667681098 (or 436667681091 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 24.
Adding to 131000304324300 its reverse (3423403000131), we get a palindrome (134423707324431).
The spelling of 131000304324300 in words is "one hundred thirty-one trillion, three hundred four million, three hundred twenty-four thousand, three hundred".
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