Base | Representation |
---|---|
bin | 111101000000000111… |
… | …0100001110110110100 |
3 | 110112010122012022122112 |
4 | 1322000032201312310 |
5 | 4121242034424340 |
6 | 140103011150152 |
7 | 12315211162412 |
oct | 1720016416664 |
9 | 415118168575 |
10 | 131000311220 |
11 | 50614295819 |
12 | 2147b8a5358 |
13 | c4791c056c |
14 | 64aa2982b2 |
15 | 361aaa7065 |
hex | 1e803a1db4 |
131000311220 has 24 divisors (see below), whose sum is σ = 291283045704. Its totient is φ = 49317764096.
The previous prime is 131000311217. The next prime is 131000311229. The reversal of 131000311220 is 22113000131.
It can be written as a sum of positive squares in 4 ways, for example, as 67095504784 + 63904806436 = 259028^2 + 252794^2 .
It is a super-2 number, since 2×1310003112202 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131000311195 and 131000311204.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131000311229) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 192647177 + ... + 192647856.
It is an arithmetic number, because the mean of its divisors is an integer number (12136793571).
Almost surely, 2131000311220 is an apocalyptic number.
131000311220 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131000311220 is an abundant number, since it is smaller than the sum of its proper divisors (160282734484).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131000311220 is a wasteful number, since it uses less digits than its factorization.
131000311220 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 385295059 (or 385295057 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 131000311220 its reverse (22113000131), we get a palindrome (153113311351).
The spelling of 131000311220 in words is "one hundred thirty-one billion, three hundred eleven thousand, two hundred twenty".
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