Base | Representation |
---|---|
bin | 11101110010010011100011… |
… | …100110010110100101011110 |
3 | 122011211111201121110201012122 |
4 | 131302103203212112211132 |
5 | 114132302124134310024 |
6 | 1142340414444502542 |
7 | 36410314035043661 |
oct | 3562234346264536 |
9 | 564744647421178 |
10 | 131000321010014 |
11 | 38816a19047755 |
12 | 128388a654aa52 |
13 | 581337b1c6881 |
14 | 244c6410c76d8 |
15 | 10229440bdd5e |
hex | 7724e399695e |
131000321010014 has 4 divisors (see below), whose sum is σ = 196500481515024. Its totient is φ = 65500160505006.
The previous prime is 131000321009959. The next prime is 131000321010071. The reversal of 131000321010014 is 410010123000131.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×1310003210100142 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131000321009974 and 131000321010001.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32750080252502 + ... + 32750080252505.
It is an arithmetic number, because the mean of its divisors is an integer number (49125120378756).
Almost surely, 2131000321010014 is an apocalyptic number.
131000321010014 is a deficient number, since it is larger than the sum of its proper divisors (65500160505010).
131000321010014 is an equidigital number, since it uses as much as digits as its factorization.
131000321010014 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65500160505009.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 131000321010014 its reverse (410010123000131), we get a palindrome (541010444010145).
The spelling of 131000321010014 in words is "one hundred thirty-one trillion, three hundred twenty-one million, ten thousand, fourteen".
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