13100032424471 has 2 divisors, whose sum is σ = 13100032424472. Its totient is φ = 13100032424470.

The previous prime is 13100032424429. The next prime is 13100032424509. The reversal of 13100032424471 is 17442423000131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13100032424471 - 2²² = 13100028230167 is a prime.

It is a super-3 number, since 3×13100032424471³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13100032424371) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550016212235 + 6550016212236.

It is an arithmetic number, because the mean of its divisors is an integer number (6550016212236).

Almost surely, 2^{13100032424471} is an apocalyptic number.

13100032424471 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100032424471 is an equidigital number, since it uses as much as digits as its factorization.

13100032424471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16128, while the sum is 32.

The spelling of 13100032424471 in words is "thirteen trillion, one hundred billion, thirty-two million, four hundred twenty-four thousand, four hundred seventy-one".