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13100103000 = 233353547887
BaseRepresentation
bin11000011001101001…
…11011010101011000
31020210222011011222000
430030310323111120
5203312111244000
610003524401000
7642430016055
oct141464732530
936728134860
1013100103000
115612737306
122657246160
13130a05034a
148c3b8602c
1551a127000
hex30cd3b558

13100103000 has 256 divisors, whose sum is σ = 45548006400. Its totient is φ = 3483043200.

The previous prime is 13100102993. The next prime is 13100103011. The reversal of 13100103000 is 30100131.

13100103000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×131001030002 (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (9).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 14768557 + ... + 14769443.

It is an arithmetic number, because the mean of its divisors is an integer number (177921900).

Almost surely, 213100103000 is an apocalyptic number.

13100103000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13100103000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22774003200).

13100103000 is an abundant number, since it is smaller than the sum of its proper divisors (32447903400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13100103000 is a wasteful number, since it uses less digits than its factorization.

13100103000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1464 (or 1444 counting only the distinct ones).

The product of its (nonzero) digits is 9, while the sum is 9.

Adding to 13100103000 its reverse (30100131), we get a palindrome (13130203131).

It can be divided in two parts, 1310010 and 3000, that added together give a triangular number (1313010 = T1620).

The spelling of 13100103000 in words is "thirteen billion, one hundred million, one hundred three thousand".