131001047 has 2 divisors, whose sum is σ = 131001048. Its totient is φ = 131001046.

The previous prime is 131001043. The next prime is 131001049. The reversal of 131001047 is 740100131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131001047 - 2² = 131001043 is a prime.

It is a super-2 number, since 2×131001047² = 34322548630192418, which contains 22 as substring.

Together with 131001049, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131001041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500523 + 65500524.

It is an arithmetic number, because the mean of its divisors is an integer number (65500524).

Almost surely, 2^131001047 is an apocalyptic number.

131001047 is a deficient number, since it is larger than the sum of its proper divisors (1).

131001047 is an equidigital number, since it uses as much as digits as its factorization.

131001047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 84, while the sum is 17.

The square root of 131001047 is about 11445.5688805756. The cubic root of 131001047 is about 507.8766608515.

Adding to 131001047 its reverse (740100131), we get a palindrome (871101178).

The spelling of 131001047 in words is "one hundred thirty-one million, one thousand, forty-seven".