1310011131103 has 4 divisors (see below), whose sum is σ = 1315230299208. Its totient is φ = 1304791963000.

The previous prime is 1310011131097. The next prime is 1310011131127. The reversal of 1310011131103 is 3011311100131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1310011131103 - 2⁹ = 1310011130591 is a prime.

It is a super-2 number, since 2×1310011131103² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310011131133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2609583676 + ... + 2609584177.

It is an arithmetic number, because the mean of its divisors is an integer number (328807574802).

Almost surely, 2^{1310011131103} is an apocalyptic number.

1310011131103 is a deficient number, since it is larger than the sum of its proper divisors (5219168105).

1310011131103 is an equidigital number, since it uses as much as digits as its factorization.

1310011131103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5219168104.

The product of its (nonzero) digits is 27, while the sum is 16.

Adding to 1310011131103 its reverse (3011311100131), we get a palindrome (4321322231234).

The spelling of 1310011131103 in words is "one trillion, three hundred ten billion, eleven million, one hundred thirty-one thousand, one hundred three".