Base | Representation |
---|---|
bin | 1011111010100001101110… |
… | …1101000001011100000101 |
3 | 1201101100200112121111202010 |
4 | 2332220123231001130011 |
5 | 3204113013422240010 |
6 | 43510035413204433 |
7 | 2521311030402450 |
oct | 276503355013405 |
9 | 51340615544663 |
10 | 13100115040005 |
11 | 41a080046a084 |
12 | 1576a82030719 |
13 | 740449276266 |
14 | 334098470497 |
15 | 17ab6da47620 |
hex | bea1bb41705 |
13100115040005 has 64 divisors (see below), whose sum is σ = 24799292448768. Its totient is φ = 5780915827200.
The previous prime is 13100115040003. The next prime is 13100115040049. The reversal of 13100115040005 is 50004051100131.
It is a happy number.
13100115040005 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13100115040005 - 21 = 13100115040003 is a prime.
It is a super-2 number, since 2×131001150400052 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13100115040003) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 17821471 + ... + 18541980.
It is an arithmetic number, because the mean of its divisors is an integer number (387488944512).
Almost surely, 213100115040005 is an apocalyptic number.
13100115040005 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13100115040005 is a deficient number, since it is larger than the sum of its proper divisors (11699177408763).
13100115040005 is a wasteful number, since it uses less digits than its factorization.
13100115040005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 36363586.
The product of its (nonzero) digits is 300, while the sum is 21.
Adding to 13100115040005 its reverse (50004051100131), we get a palindrome (63104166140136).
The spelling of 13100115040005 in words is "thirteen trillion, one hundred billion, one hundred fifteen million, forty thousand, five".
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