131002144040440 has 32 divisors (see below), whose sum is σ = 294757929180000. Its totient is φ = 52400305600384.

The previous prime is 131002144040437. The next prime is 131002144040491. The reversal of 131002144040440 is 44040441200131.

It is a junction number, because it is equal to n+sod(n) for n = 131002144040399 and 131002144040408.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13395340 + ... + 21010459.

It is an arithmetic number, because the mean of its divisors is an integer number (9211185286875).

Almost surely, 2^{131002144040440} is an apocalyptic number.

131002144040440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131002144040440 is an abundant number, since it is smaller than the sum of its proper divisors (163755785139560).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131002144040440 is a wasteful number, since it uses less digits than its factorization.

131002144040440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34500999 (or 34500995 counting only the distinct ones).

The product of its (nonzero) digits is 6144, while the sum is 28.

Adding to 131002144040440 its reverse (44040441200131), we get a palindrome (175042585240571).

The spelling of 131002144040440 in words is "one hundred thirty-one trillion, two billion, one hundred forty-four million, forty thousand, four hundred forty".