Base | Representation |
---|---|
bin | 1011111010100010011101… |
… | …1001100001010011010000 |
3 | 1201101101012012211020001102 |
4 | 2332220213121201103100 |
5 | 3204113414140113344 |
6 | 43510111102523532 |
7 | 2521315632241535 |
oct | 276504731412320 |
9 | 51341165736042 |
10 | 13100311254224 |
11 | 41a08a11a6797 |
12 | 1576b178965a8 |
13 | 74047ab0634c |
14 | 3340b6548d8c |
15 | 17ab80da4e4e |
hex | bea276614d0 |
13100311254224 has 20 divisors (see below), whose sum is σ = 25381933442244. Its totient is φ = 6550134882048.
The previous prime is 13100311254211. The next prime is 13100311254241. The reversal of 13100311254224 is 42245211300131.
It is a happy number.
It can be written as a sum of positive squares in 2 ways, for example, as 5388582254224 + 7711729000000 = 2321332^2 + 2777000^2 .
It is a super-4 number, since 4×131003112542244 (a number of 54 digits) contains 4444 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4774724 + ... + 6999900.
Almost surely, 213100311254224 is an apocalyptic number.
It is an amenable number.
13100311254224 is a deficient number, since it is larger than the sum of its proper divisors (12281622188020).
13100311254224 is a wasteful number, since it uses less digits than its factorization.
13100311254224 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2593142 (or 2593136 counting only the distinct ones).
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 13100311254224 its reverse (42245211300131), we get a palindrome (55345522554355).
The spelling of 13100311254224 in words is "thirteen trillion, one hundred billion, three hundred eleven million, two hundred fifty-four thousand, two hundred twenty-four".
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