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13100311254224 = 243679572225177
BaseRepresentation
bin1011111010100010011101…
…1001100001010011010000
31201101101012012211020001102
42332220213121201103100
53204113414140113344
643510111102523532
72521315632241535
oct276504731412320
951341165736042
1013100311254224
1141a08a11a6797
121576b178965a8
1374047ab0634c
143340b6548d8c
1517ab80da4e4e
hexbea276614d0

13100311254224 has 20 divisors (see below), whose sum is σ = 25381933442244. Its totient is φ = 6550134882048.

The previous prime is 13100311254211. The next prime is 13100311254241. The reversal of 13100311254224 is 42245211300131.

It is a happy number.

It can be written as a sum of positive squares in 2 ways, for example, as 5388582254224 + 7711729000000 = 2321332^2 + 2777000^2 .

It is a super-4 number, since 4×131003112542244 (a number of 54 digits) contains 4444 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4774724 + ... + 6999900.

Almost surely, 213100311254224 is an apocalyptic number.

It is an amenable number.

13100311254224 is a deficient number, since it is larger than the sum of its proper divisors (12281622188020).

13100311254224 is a wasteful number, since it uses less digits than its factorization.

13100311254224 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2593142 (or 2593136 counting only the distinct ones).

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 13100311254224 its reverse (42245211300131), we get a palindrome (55345522554355).

The spelling of 13100311254224 in words is "thirteen trillion, one hundred billion, three hundred eleven million, two hundred fifty-four thousand, two hundred twenty-four".

Divisors: 1 2 4 8 16 367957 735914 1471828 2225177 2943656 4450354 5887312 8900708 17801416 35602832 818769453389 1637538906778 3275077813556 6550155627112 13100311254224