131003113 has 2 divisors, whose sum is σ = 131003114. Its totient is φ = 131003112.

The previous prime is 131003111. The next prime is 131003149. The reversal of 131003113 is 311300131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 129777664 + 1225449 = 11392^2 + 1107^2 .

It is an emirp because it is prime and its reverse (311300131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131003113 - 2¹ = 131003111 is a prime.

Together with 131003111, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 131003093 and 131003102.

It is not a weakly prime, because it can be changed into another prime (131003111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65501556 + 65501557.

It is an arithmetic number, because the mean of its divisors is an integer number (65501557).

Almost surely, 2^131003113 is an apocalyptic number.

It is an amenable number.

131003113 is a deficient number, since it is larger than the sum of its proper divisors (1).

131003113 is an equidigital number, since it uses as much as digits as its factorization.

131003113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27, while the sum is 13.

The square root of 131003113 is about 11445.6591334881. The cubic root of 131003113 is about 507.8793307225.

Adding to 131003113 its reverse (311300131), we get a palindrome (442303244).

The spelling of 131003113 in words is "one hundred thirty-one million, three thousand, one hundred thirteen".