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13100340432103 = 34570137895003
BaseRepresentation
bin1011111010100010100100…
…1000110100110011100111
31201101101021020201121120121
42332220221020310303213
53204113444122311403
643510114024142411
72521316435244331
oct276505110646347
951341236647517
1013100340432103
1141a0906715541
121576b25607a07
13740483b81072
143340ba382451
1517ab8371a3bd
hexbea29234ce7

13100340432103 has 4 divisors (see below), whose sum is σ = 13100378672808. Its totient is φ = 13100302191400.

The previous prime is 13100340432079. The next prime is 13100340432181. The reversal of 13100340432103 is 30123404300131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13100340432103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13100340432503) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18601801 + ... + 19293202.

It is an arithmetic number, because the mean of its divisors is an integer number (3275094668202).

Almost surely, 213100340432103 is an apocalyptic number.

13100340432103 is a deficient number, since it is larger than the sum of its proper divisors (38240705).

13100340432103 is an equidigital number, since it uses as much as digits as its factorization.

13100340432103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38240704.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 13100340432103 its reverse (30123404300131), we get a palindrome (43223744732234).

The spelling of 13100340432103 in words is "thirteen trillion, one hundred billion, three hundred forty million, four hundred thirty-two thousand, one hundred three".

Divisors: 1 345701 37895003 13100340432103