Base | Representation |
---|---|
bin | 1011111010100010111000… |
… | …0101010111011011001101 |
3 | 1201101101111000212101210002 |
4 | 2332220232011113123031 |
5 | 3204114131343131110 |
6 | 43510130150454045 |
7 | 2521321463456441 |
oct | 276505605273315 |
9 | 51341430771702 |
10 | 13100423411405 |
11 | 41a0949541080 |
12 | 1576b49364325 |
13 | 740498115545 |
14 | 3340c73c2821 |
15 | 17ab8ab5baa5 |
hex | bea2e1576cd |
13100423411405 has 8 divisors (see below), whose sum is σ = 17149645193184. Its totient is φ = 9527580662800.
The previous prime is 13100423411287. The next prime is 13100423411429. The reversal of 13100423411405 is 50411432400131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13100423411405 - 222 = 13100419217101 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 119094758231 + ... + 119094758340.
It is an arithmetic number, because the mean of its divisors is an integer number (2143705649148).
Almost surely, 213100423411405 is an apocalyptic number.
It is an amenable number.
13100423411405 is a deficient number, since it is larger than the sum of its proper divisors (4049221781779).
13100423411405 is a wasteful number, since it uses less digits than its factorization.
13100423411405 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 238189516587.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 13100423411405 its reverse (50411432400131), we get a palindrome (63511855811536).
The spelling of 13100423411405 in words is "thirteen trillion, one hundred billion, four hundred twenty-three million, four hundred eleven thousand, four hundred five".
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