13100431142 has 4 divisors (see below), whose sum is σ = 19650646716. Its totient is φ = 6550215570.

The previous prime is 13100431079. The next prime is 13100431199. The reversal of 13100431142 is 24113400131.

13100431142 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 24113400131 = 49339 ⋅488729.

It is a super-2 number, since 2×13100431142² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3275107784 + ... + 3275107787.

It is an arithmetic number, because the mean of its divisors is an integer number (4912661679).

Almost surely, 2^13100431142 is an apocalyptic number.

13100431142 is a deficient number, since it is larger than the sum of its proper divisors (6550215574).

13100431142 is an equidigital number, since it uses as much as digits as its factorization.

13100431142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6550215573.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 13100431142 its reverse (24113400131), we get a palindrome (37213831273).

The spelling of 13100431142 in words is "thirteen billion, one hundred million, four hundred thirty-one thousand, one hundred forty-two".