13100539 has 2 divisors, whose sum is σ = 13100540. Its totient is φ = 13100538.

The previous prime is 13100531. The next prime is 13100561. The reversal of 13100539 is 93500131.

It is an a-pointer prime, because the next prime (13100561) can be obtained adding 13100539 to its sum of digits (22).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13100539 - 2³ = 13100531 is a prime.

It is a Chen prime.

It is equal to p₈₅₅₃₁₀ and since 13100539 and 855310 have the same sum of digits, it is a Honaker prime.

It is not a weakly prime, because it can be changed into another prime (13100531) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550269 + 6550270.

It is an arithmetic number, because the mean of its divisors is an integer number (6550270).

Almost surely, 2^13100539 is an apocalyptic number.

13100539 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100539 is an equidigital number, since it uses as much as digits as its factorization.

13100539 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 405, while the sum is 22.

The square root of 13100539 is about 3619.4666734203. The cubic root of 13100539 is about 235.7380688233.

It can be divided in two parts, 131005 and 39, that added together give a square (131044 = 362²).

The spelling of 13100539 in words is "thirteen million, one hundred thousand, five hundred thirty-nine".