131010144113111 has 8 divisors (see below), whose sum is σ = 131210561398224. Its totient is φ = 130809733528320.

The previous prime is 131010144113099. The next prime is 131010144113131. The reversal of 131010144113111 is 111311441010131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131010144113111 - 2⁴² = 126612097602007 is a prime.

It is a super-2 number, since 2×131010144113111² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131010144113131) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 38185256 + ... + 41474498.

It is an arithmetic number, because the mean of its divisors is an integer number (16401320174778).

Almost surely, 2^{131010144113111} is an apocalyptic number.

131010144113111 is a deficient number, since it is larger than the sum of its proper divisors (200417285113).

131010144113111 is an equidigital number, since it uses as much as digits as its factorization.

131010144113111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3350161.

The product of its (nonzero) digits is 144, while the sum is 23.

Adding to 131010144113111 its reverse (111311441010131), we get a palindrome (242321585123242).

The spelling of 131010144113111 in words is "one hundred thirty-one trillion, ten billion, one hundred forty-four million, one hundred thirteen thousand, one hundred eleven".