131010201130301 has 4 divisors (see below), whose sum is σ = 131532154123104. Its totient is φ = 130488248137500.

The previous prime is 131010201130283. The next prime is 131010201130399. The reversal of 131010201130301 is 103031102010131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131010201130301 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131010201130301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131010201138301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 260976496025 + ... + 260976496526.

It is an arithmetic number, because the mean of its divisors is an integer number (32883038530776).

Almost surely, 2^{131010201130301} is an apocalyptic number.

It is an amenable number.

131010201130301 is a deficient number, since it is larger than the sum of its proper divisors (521952992803).

131010201130301 is an equidigital number, since it uses as much as digits as its factorization.

131010201130301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 521952992802.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 131010201130301 its reverse (103031102010131), we get a palindrome (234041303140432).

The spelling of 131010201130301 in words is "one hundred thirty-one trillion, ten billion, two hundred one million, one hundred thirty thousand, three hundred one".