Base | Representation |
---|---|
bin | 11000011001110001… |
… | …01111110001100111 |
3 | 1020211001001001101122 |
4 | 30030320233301213 |
5 | 203312340313411 |
6 | 10004002044155 |
7 | 642441356105 |
oct | 141470576147 |
9 | 36731031348 |
10 | 13101104231 |
11 | 5613260576 |
12 | 265764965b |
13 | 130a310ca7 |
14 | 8c3d66c75 |
15 | 51a2739db |
hex | 30ce2fc67 |
13101104231 has 2 divisors, whose sum is σ = 13101104232. Its totient is φ = 13101104230.
The previous prime is 13101104197. The next prime is 13101104243. The reversal of 13101104231 is 13240110131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13101104231 - 210 = 13101103207 is a prime.
It is a super-2 number, since 2×131011042312 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13101104831) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550552115 + 6550552116.
It is an arithmetic number, because the mean of its divisors is an integer number (6550552116).
Almost surely, 213101104231 is an apocalyptic number.
13101104231 is a deficient number, since it is larger than the sum of its proper divisors (1).
13101104231 is an equidigital number, since it uses as much as digits as its factorization.
13101104231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 13101104231 its reverse (13240110131), we get a palindrome (26341214362).
The spelling of 13101104231 in words is "thirteen billion, one hundred one million, one hundred four thousand, two hundred thirty-one".
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